study-freak
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Using Newton's Method, under what conditions will a better estimate NOT be reached?
If the initial estimate is at a stationary point or if there is a turning point between the initial estimate and the actual root...
Or if at P(z1) and P''(z1) have opposite signs, where x=z1 is the first approximation.
Now, you've initially stated that if "P(z1) and P''(z1) have opposite signs, where x=z1 is the first approximation," a better estimate NOT be reached using Newton's Method.I never really encountered a question that involved the closeness of a root. I shall have a look later but nevertheless the signs of P(z1) and P"(z1) do matter, which is what I said initially.
That's a bit more than "the signs of P(z1) and P"(z1) do matter."