Fitzpatrick 4U Ex. 33 (a) Q15 [Integration] (1 Viewer)

[Pyrobooby]

I realise this is from the 4U book, but the question looks to be a 3Uish.

I just can't figure this one out :/

 

[hscishard]

I realise this is from the 4U book, but the question looks to be a 3Uish.

I just can't figure this one out :/

Think the method is
cos2x = 1-2sin^2x
(1-cos2x)/2 = sin^2x

 

[Shadowdude]

You're integrating with respect to... what?

 

[Bored Of Fail1]

yes you approach it the same way you would do sin^2(x)

its relatively standard

 

[benji_10]

cos(2A) = 1-2sin^2(A)
sin^2(A) = (1-cos(2A))/2
If A = x - (pi/4), then 2A = 2x - (pi/2)

Then you substitute the integrand with 1-cos(2x-(pi/2)) . 0.5
And then you integrate it.