jessica2011hsc
Member
- Joined
- Feb 13, 2011
- Messages
- 42
- Gender
- Female
- HSC
- 2011
my school is behind in this topic, so im trying to accelerate. that's why i asked this question, cause im not completely sure how to do it with confidence
Curve is increasing. (Curve going down at a particular range)my school is behind in this topic, so im trying to accelerate. that's why i asked this question, cause im not completely sure how to do it with confidence
lol: know yu cant said 2, unit mths is piss esyP(x)=ax^3+bx^2+cx+d P(0) = 5 = d
P'(x)=3ax^2+2bx+c
0 = 3ax^2 + 2bx + c for stat points.
0 = 3a + 2b + c 0 = 12a - 4b + c
12a - 3a - 4b -2 b + c - c = 0
9a - 6b = 0
3a - 2b = 0
P(1) = 12 P(-2) = 15
Hence, a + b + c + d = 12 -8a + 4b - 2c + d = 15
a + 8a + b - 4b + c + 2c + d - d = 12 - 15
9a - 3b + 3c = -3
3a - b + c = -1
3a - 3a + b + 2b + c - c = 0 + 1
3b = 1
b = 1/3
9a - 5(1/3) = 0
9a = 2.5
a = 5/27
3(5/27) - 1/3 + c = -1
c = -1 - 15/27 + 1/3
c = -11/9
a + b + c + d = 12
5/27 + 1/3 - 11/9 + d = 12
d = 12 - 5/27 -1/3 + 11/9
This is wrong... lol
I haven't worked it out, but from the line:
Stationary when
Substitute back,
this i'm am finding difficulty. please provide some form of help : [Make y the subject,find intersection points and graph it. Then you just do it
What is wrong with your language?lol: know yu cant said 2, unit mths is piss esy
Lmao
x^2 +4x + 4 = 4x - x^2(x+2)^2 = 4x-x^2
Then solve
lol thats the worst display of algebra I have ever seen(x+2)(x+2) = x^2 + 4x + 4
therefore x = 4x - x^2 - 2
To all above attempting this question, learn to read properly.Question: http://imgur.com/SZkDD
um hii guys, I'm stuck on this question and don't know what the intercept of the 2 curves are. thankss
Ha, no it was just me. I think they assumed what I was saying was correctTo all above attempting this question, learn to read properly.
differentiate <a href="http://www.codecogs.com/eqnedit.php?latex=\displaystyle x\sqrt{x@plus;1}" target="_blank"><img src="http://latex.codecogs.com/gif.latex?\displaystyle x\sqrt{x+1}" title="\displaystyle x\sqrt{x+1}" /></a>