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partial fractions? (1 Viewer)

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(3x+2)/(x(x+1)^3)
Do it in the form A/x + B/(x+1) + C/(x+1)^2 + D/(x+1)^3

That should be a key as it has 3 repeated linear factors of (x+1)

you should then get A(x+1)^3 + Bx(x+1)^2 + C(x+1) + Dx = 3x + 2

then use substitution methods to find out the answer :p

In this case, A = 2, B = -2, C = -2, and D = 1
 
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