MedVision ad

Another question about permutations (1 Viewer)

goobi

Member
Joined
Oct 6, 2010
Messages
196
Gender
Male
HSC
2012
I'm really stuck with permutations which is the most difficult Extension 1 topic for me so yeah...
Okay so the question is:

Ten balls of identical size are placed side by side in a line. If 4 balls are read in colour, 3 are blue and 2 are green and 1 is white, in how many arrangements will there be a red ball at each end?

The answer is 1680 but I don't know how to get it.

Thanks for any help again!
 
Last edited:

Mature Lamb

wats goin on
Joined
May 14, 2009
Messages
1,117
Gender
Male
HSC
2010
Uni Grad
2015
Set 2 red balls, one at each end.

You will have 2 red balls, 3 blue balls, 2 green balls, and 1 white ball left to arrange in the middle.
 

goobi

Member
Joined
Oct 6, 2010
Messages
196
Gender
Male
HSC
2012
Set 2 red balls, one at each end.

You will have 2 red balls, 3 blue balls, 2 green balls, and 1 white ball left to arrange in the middle.
So, do you think this solution is correct?
8!2! / 2!3!2!2!
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top