how big a change is yr 11 maths to yr 10 maths (1 Viewer)

[SpiralFlex]

lol i didnt know. i went to have my dinner.

Okay. Home and Away is on. Goodbye.

 

[bleakarcher]

btw my other 'solution' was never a solution. i knew half way through i was wrong.

 

[bleakarcher]

anyone feel free to post more questionz...

 

[Drongoski]

I want to go meet Salman Khan and offer my assistance. After a few months north. I will come back and teach.

You don't happen to be South Asian?

 

[AAEldar]

anyone feel free to post more questionz...

 

[SpiralFlex]

You don't happen to be South Asian?

Why? I am one of a kind. A robotron V 3000. Maybe, why?

 

[bleakarcher]

Using one application of integration by parts:
Integral[log[10]x] dx
=xlog[10]x-x+C

 

[Drongoski]

Why? I am one of a kind. A robotron V 3000. Maybe, why?

Very few on bos, not familiar with the Bollywood scene, would have heard of Salman Khan.

 

[AAEldar]

Using one application of integration by parts:
Integral[log[10]x] dx
=xlog[10]x-x+C

This would work if the logarithm was to the base e.

And Drongoski, I know of Salman Khan - I follow him pretty often actually, see whats updated/where he's done talks.

 

[bleakarcher]

lol. india is in east asia. salman khan is this guy that started on youtube uploading a tutoring video for his cousin lol. since then his become a phenomenon. his vidz are great

 

[bleakarcher]

oh right sorry. i didnt know that lol. i did that question from memory. ill do it now

 

[bleakarcher]

xlog[10]x-[x/ln(10)]+C

 

[Drongoski]

But people from India, Pakistan, Bangladesh & Sri Lanka are referred to as South Asians.

I remember that guy. He is also Salman Khan?

 

[AAEldar]

xlog[10]x-[x/ln(10)]+C

Still not right. It seems you've got the right idea but you've messed up somewhere...

 

[Drongoski]

Using one application of integration by parts:
Integral[log[10]x] dx
=xlog[10]x-x+C

bleak

If you already know integration by parts in year 10, what were you bellyaching about doing MX1? By Yr 11 you'd be capable of sitting the MX1 & MX2 exams. You'll get ATAR of 99.99.

 

[bleakarcher]

isnt the derivative of log[10]x=1/(xln(10)

 

[AAEldar]

bleak

If you already know integration by parts in year 10, what were you bellyaching about doing MX1? By Yr 11 you'd be capable of sitting the MX1 & MX2 exams. You'll get ATAR of 99.99.

Agreed. You're already much further ahead than some Year 12 students.

isnt the derivative of log[10]x=1/(xln(10)

Yes, it is. However remember you're integrating , there's no need to differentiate that function.

 

[bleakarcher]

can u plz post the solution?

 

[AAEldar]

can u plz post the solution?

 

[bleakarcher]

ahh yeh. i was completely unaware of the change of base formula. so u use that wen integrating logarithm functions of a base other than e?