Answer my stupid maths question! (2 Viewers)

Dylanamali

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When dividing a line externally in a ratio, to which number do you apply the negative to?

E.g. A is the point (-2,-1) and B is the point (1,5). Find the coordinates of the point Q which divides AB externally in the ratio 5:2.

I always thought you just stick it in front of the 5, however the answers put it in front of the 2 and each of these produced different results.

So please tell me which one and the reasoning..

Thank you for answering my STUPID question haha =)
 

SpiralFlex

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Does not matter, they are still in the same ratio.

Think of



and



Same thing.
 

SpiralFlex

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Also. The only stupid question you can ask is the one that you don't ask. So you better ask or else you will not know.
 

Dylanamali

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ANOTHER MATHS Q:


Evaluate exactly, sorry about the brackets, meant to be around the sin 7pie on 6
 

Dylanamali

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its worth 2 marks.. I know what I'm doing but I'm not sure if I'm getting 2 marks

I just get the exact value for sin 7pi/6 which is -1/2 then sin-1 that.. to get -pi/6.
 

Hermes1

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its worth 2 marks.. I know what I'm doing but I'm not sure if I'm getting 2 marks

I just get the exact value for sin 7pi/6 which is -1/2 then sin-1 that.. to get -pi/6.
you have to do this:

(bcuz inverse sin x is an odd function)
 

Hermes1

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its worth 2 marks.. I know what I'm doing but I'm not sure if I'm getting 2 marks

I just get the exact value for sin 7pi/6 which is -1/2 then sin-1 that.. to get -pi/6.
this is also right obviously. bcuz if its only 2 marks they wont really care wat way u do it as long as u show a few lines of working
 

Dylanamali

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did you FIND IT a lil difficult..??? like I just did CSSA 2009 and it was preety sweet, moved onto 2010 and was like ****.. this aint that nice..
 

Hermes1

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did you FIND IT a lil difficult..??? like I just did CSSA 2009 and it was preety sweet, moved onto 2010 and was like ****.. this aint that nice..
CSSA 2009 was really easy. 2010 was also pretty easy, i only had a problem with the last part of the parametrics question, that was only 1 mark tho.
The 2010 paper the las question was weird as.
 

Shadowdude

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Pro-tip: Draw a diagram and figure it out that way.
 

Omnipotence

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Don't you substitute the values into the formula?
Q(x) = mx(2)-nx(1)/m-n
and
Q(y) = my(2)-nx(1)/m-n
 

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