Q9c (1 Viewer)

[someth1ng]

Who got this...



It's a shitty picture - I know.

 

[sinsolja]

Who got this...

View attachment 23396

It's a shitty picture - I know.

Yes along the same lines. but is your point at 3 meant to be V shaped?

 

[jamesfirst]

I got similar but instead, I made the end part go above the x axis..

OMGGGGGGGGGGGG I'm losing 1 mark.......

 

[_pizza]

Yep exactly right, but I'd make it less pointy lol. You wouldn't get marked down for that though, its just emphasising the transition between decreasing negative grad and increasing negative grad a bit much.

 

[someth1ng]

Yes along the same lines. but is your point at 3 meant to be V shaped?

I think so...

 

[KGZ9]

I got similar but instead, I made the end part go above the x axis..

OMGGGGGGGGGGGG I'm losing 1 mark.......

thats what i did aswell. STUPID MISTAKES ARE KILLING ME

 

[jamesfirst]

I think so...

It's not meant to be a V-shaped....


It's an STP got dammit

 

[mitchh81]

but since x=3 its is a point of inflexion, so the concavity would change, therefore be above the x axis

 

[someth1ng]

but since x=3 its is a point of inflexion, so the concavity would change, therefore be above the x axis

Errr...

 

[someth1ng]

It's not meant to be a V-shaped....


It's an STP got dammit

Why?

 

[jamesfirst]

Why?

x=3 was the POI on f(x) therefore it would be an STP for f'(x)

but since x=3 its is a point of inflexion, so the concavity would change, therefore be above the x axis

Actually, this makes sense... I think it might go above the x-axis.

 

[sinsolja]

but since x=3 its is a point of inflexion, so the concavity would change, therefore be above the x axis

Nope a point of inflexion for F(x), and in turn a stationary point for Dy/dx. - and you dont know if its a inflexion point for dy/dx
Its not meant not be Vshaped:S

 

[someth1ng]

x=3 was the POI on f(x) therefore it would be an STP for f'(x)
Actually, this makes sense... I think it might go above the x-axis.

What's STP --> S Turning Point...What's the S? How can it possibly go above the x-axis? The gradient is always negative.

Is it supposed to be pointed or not?

 

[jamesfirst]

What's STP --> S Turning Point...What's the S? How can it possibly go above the x-axis? The gradient is always negative.

But if it's POI there should be a concavity change shouldn't it?

 

[jamesfirst]

What's STP --> S Turning Point...What's the S? How can it possibly go above the x-axis? The gradient is always negative.

Is it supposed to be pointed or not?

STP = stationary points.

 

[sinsolja]

But if it's POI there should be a concavity change shouldn't it?

Concavity of F(x) not f, dash (x)

 

[someth1ng]

But if it's POI there should be a concavity change shouldn't it?

Yes but it doesn't mean that it's above the x-axis.

 

[sinsolja]

Yes but it doesn't mean that it's above the x-axis.

Correct , but it isn't pointed however. Its more curvy.

 

[jamesfirst]

Concavity of F(x) not f, dash (x)

If the concavity changes for f(x), doesn't that mean that f '(x) will reach positive because the concavity of f(x) has changed????


Do you get what I mean ?? Argh fk it, I probably did it wrong LOL

 

[someth1ng]

Correct , but it isn't pointed however. Its more curvy.

How is more "curvy" though - that would just create more inflexion points?