Polynomials Qn! (1 Viewer)

[Lindurr]

When the polynomial P(x) is divided by (x^2-1) the remainder is 3x-1.
What is the remainder when P(x) is divided by (x-1)

 

[happykushan]

P(X) = (X^2-1)Q(X) +(3x-1)
= (x-1)(x+1)Q(X) + (3x-1)
Therefore, P(1) = (1-1)(1+1)Q(X) + (3(1)-1)
= 2

 

[michaeljennings]

Its still 3x-1 isen it? haha

the answer is two

P(x) = (x^2-1).Q(x) +(3x-1)

P(1) = 0 +3-1 = 2

 

[SpiralFlex]

Division identity statement.







The remainder is

Edit: I am getting slower these days...

 

[michaeljennings]

P(X) = (X^2-1)Q(X) +(3x-1)
= (x-1)(x+1)Q(X) + (3x-1)
Therefore, p(1) = (1-1)(1+1)Q(X) + (3(1)-1)
= 2

Lol nice edit genius...

 

[barbernator]

lol nice edit genius...

owned!

 

[happykushan]

Lol nice edit genius...

lol embarrassment

 

[michaeljennings]

owned!

hahaha I had quoted what he said anyway LOL so he cant hide!!!

 

[happykushan]

hahaha I had quoted what he said anyway LOL so he cant hide!!!

i corrected myself! but you were too quick.

 

[Lindurr]

Thanks heap! The answer they had was so weird! The way you guys did it was way easier!