SpiralFlex
Well-Known Member
- Joined
- Dec 18, 2010
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- 6,960
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Okay. I make no promises I will not fall asleep though...It's late so I am going at a slower pace.Spiralflex, as you know from my PM to you I'd rather you just go through y=[f(x)]^2 and y=[f(x)]^3. I understand y=1/[f(x)] graphs now. Just to save you the effort.