I have found out the values for the fraction so here it is: \frac{x}{(x+3)(x-1)}=\frac{3}{4(x+3)} + \frac{1}{4(x-1)} Integrate \frac{x}{(x+3)(x-1)}dx I am partially (lame pun >.>) confused with integrating \frac{3}{4(x+3)} because I don't know what value to multiply the fraction by when using the integration log rule.