Integration (1 Viewer)

[atar90plus]

Hello
Could you guys please help me with these integration Q's. Our teacher only taught us the 5 basic rules of integration since my class is only at the start of the topic.

i) 5x(x^3-rootx) dx

j) (2x-1) (x+3) dx

o) (root x -1)^2 / 5 root x dx

 

[Timothy6340]

I) 5x(x^3-rootx)dx
= 5x(x^3-X^1/2)dx
= 5x^4-5x^3/2 dx
now u can intergrate normally
(5x^5)/5-(5x^5/2)/5/2 + c
=x^5 - 2rootx^5 +c

J) (2x-1)(x+3) dx
=2x^2-x+6x-3 dx
= 2x^2 +5x-3 dx
=(2x^3)/3 +(5x^2)/2-3x +c
please correct me if im wrong

 

[Timske]

+ C

 

[funnytomato]

Hello
Could you guys please help me with these integration Q's. Our teacher only taught us the 5 basic rules of integration since my class is only at the start of the topic.

i) 5x(x^3-rootx) dx

j) (2x-1) (x+3) dx

o) (root x -1)^2 / 5 root x dx

has your teacher taught this

?

 

[Timske]

has your teacher taught this

?

lol obviously...

 

[Timske]

Is question O this?
<a href="http://www.codecogs.com/eqnedit.php?latex=\frac{(\sqrt{x - 1})^2}{5\sqrt{x}}" target="_blank"><img src="http://latex.codecogs.com/gif.latex?\frac{(\sqrt{x - 1})^2}{5\sqrt{x}}" title="\frac{(\sqrt{x - 1})^2}{5\sqrt{x}}" /></a>

 

[zeebobDD]

Is question O this?

na i think its rootx -1 whole thing squared

so use the substitution u = rootx

 

[rolpsy]

o)