Linear functions help (1 Viewer)

[girlworld_club]

If points (3k, 1) (k -1, k-3) and (k-4, k-5) are collinear (have the same gradient) find K.

 

[fortune_cookie]

If points (3k, 1) (k -1, k-3) and (k-4, k-5) are collinear (have the same gradient) find K.

A( 3k,1) , B (k-1, k-3) & C (k-4, k-5)

m AB = [ (k-3) - 1 ] / [(k-1) -3k] = [ k-4 ] / [ -2k-1]


m BC = [ (k-5) - (k-3) ] / [ (k-4) - (k-1)] = [ -2 ] / [ -3] = 2/3

m AB = m BC

[k-4]/[-2k -1] = 2/3

3(k-4) = 2(-2k-1)

3k -12 = -4k -2

7k = 10

k = (10/7)

 

[girlworld_club]

the answer in my books is 6.somthing

 

[girlworld_club]

bump?

 

[barbernator]

A( 3k,1) , B (k-1, k-3) & C (k-4, k-5)

m AB = [ (k-3) - 1 ] / [(k-1) -3k] = [ k-4 ] / [ -2k-1]


m BC = [ (k-5) - (k-3) ] / [ (k-4) - (k-1)] = [ -2 ] / [ -3] = 2/3

m AB = m BC

[k-4]/[-2k -1] = 2/3

3(k-4) = 2(-2k-1)

3k -12 = -4k -2

7k = 10

k = (10/7)

this solution is correct

 

[theind1996]

If points (3k, 1) (k -1, k-3) and (k-4, k-5) are collinear (have the same gradient) find K.

And you do MX2?

 

[Timske]

Because she does MX2 does not simply imply that everything is easy, just sayin

 

[girlworld_club]

i don't get how he set it like that, don't make no bloody sense.

 

[girlworld_club]

it's usually the basic stuff that end up getting to me.

 

[Sy123]

it's usually the basic stuff that end up getting to me.

Ill give you a latex version

If you think you should be able to do 4u math, then you need the basics grounded first, no matter how good you are with other questions and advanced things

 

[fortune_cookie]

m BC is wrong

-5-(-3) =-2 , not -4

 

[Sy123]

Yeah I saw it heh, Im still a bit klunky with latex.

 

[girlworld_club]

just wondering where you got the -2k-1 in third line of your working.

 

[Sy123]

addition of like terms.

(k-1) - 3k = k-1-3k = k-3k-1 = -2k-1

 

[girlworld_club]

i get it, it's how i originally solved the question but did a silly sbstitution mistake. Just a header, when putting an = sign always use a new line, i though the = represented that for example x=y (meaning they should be the same). and not that after solving x you should get y

 

[zeebobDD]

i get it, it's how i originally solved the question but did a silly sbstitution mistake. Just a header, when putting an = sign always use a new line, i though the = represented that for example x=y (meaning they should be the same). and not that after solving x you should get y

lol are your subjects legit, not referring to your ability not to do this question