Concentration q (1 Viewer)

hscwav2012

Member
Joined
Mar 23, 2012
Messages
245
Location
Sydney
Gender
Male
HSC
2012
Given Acetic Acid (CH3COOH) has a density of 1.05g/mL and molecular weight of 60.052g.

What is its concentration?
 

Alkanes

Active Member
Joined
May 20, 2010
Messages
1,417
Gender
Male
HSC
2012
Hmm I think its missing some info here. What is its given mass?
 

Alkenes

Member
Joined
May 16, 2012
Messages
250
Gender
Undisclosed
HSC
N/A
use density= mass/volume to find volume

then use n=m/MM to find the no of moles

then use c=n/v to find conc.
 

Alkanes

Active Member
Joined
May 20, 2010
Messages
1,417
Gender
Male
HSC
2012
Please do it. My chemistry is so out of touch these days.
 

Alkanes

Active Member
Joined
May 20, 2010
Messages
1,417
Gender
Male
HSC
2012
use density= mass/volume to find volume

then use n=m/MM to find the no of moles

then use c=n/v to find conc.
Problem is how to find m in order to find the moles?
 

Alkenes

Member
Joined
May 16, 2012
Messages
250
Gender
Undisclosed
HSC
N/A
something is miising from question.....either the no of moles of acetic acid or the mass....re check mate
 

RealiseNothing

what is that?It is Cowpea
Joined
Jul 10, 2011
Messages
4,591
Location
Sydney
Gender
Male
HSC
2013
Problem is how to find m in order to find the moles?
"1.05g/mL"

Can we just assume that there is 1mL of solution, so the mass is 1.05g? Since we are working out the concentration, the exact amount doesn't matter, only the ratio?
 

Alkanes

Active Member
Joined
May 20, 2010
Messages
1,417
Gender
Male
HSC
2012
I'm not too sure actually. But it sounds right.
 

RealiseNothing

what is that?It is Cowpea
Joined
Jul 10, 2011
Messages
4,591
Location
Sydney
Gender
Male
HSC
2013


Assume there is 1mL, since the concentration is a ratio, not an amount. So:

m = 1.05g
M = 60.052g
V = 0.001L

Therefore:



Just put that into a calculator.
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top