solve simple (1 Viewer)

[girlworld_club]

x^2 > a^2

how do you solve?

 

[twinklegal19]

x^2 > a^2

how do you solve?

x^2-a^2>0
(x-a)(x+a)>0
x<-a or x>a

 

[Carrotsticks]

Sketch y=x^2 and y=a^2 (horizontal line) and see where they intersect (x=plus/minus a).

So from the graph, the parabola y=x^2 is only above the line when x > a or x < -a.