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Quadratic Inequality (1 Viewer)

Thread starter juantheron
Start date Aug 21, 2012

J

juantheron

Active Member

#1

$\bf{If \; -5 \leq \frac{x^2+ax+b}{x^2+2x+3}\leq 4\;\; and \;\; a,b\in \mathbb{N}. \; Then \; a^2+b^2\; = }$

A

abecina

Member

#2

juantheron said:
$\bf{If \; -5 \leq \frac{x^2+ax+b}{x^2+2x+3}\leq 4\;\; and \;\; a,b\in \mathbb{N}. \; Then \; a^2+b^2\; = }$

Well, the trivial case of a = 2 and b = 3, definitely sits the function between -5 and 4. Should that 4 be -4?

Last edited: Aug 22, 2012

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