MX2 (1 Viewer)

[tomp1612]

This may sound like a stupid question but in the 2009 HSC question 3 part iii i dont know the steps on ho to draw the graph, could anyone help??

 

[tomp1612]

bump

 

[J2good4u]

Hey,
The way to solve this question would be first look at where the curve crosses the x axis at x=4. so i put x=2 in f(x^2) which would yield 4. So at x=2 the y coodinate is 0 as that was what it was for 4. now repeat for a couple of coodinates. e.g for x=9 the curve is approaching the horizontal symptote y= -3 so put in x=3 in y=f(x^2) to get 9 and so at x=3 draw the new curve approaching -3

i know it complex but thats the way i do them

 

[tomp1612]

Hey,
The way to solve this question would be first look at where the curve crosses the x axis at x=4. so i put x=2 in f(x^2) which would yield 4. So at x=2 the y coodinate is 0 as that was what it was for 4. now repeat for a couple of coodinates. e.g for x=9 the curve is approaching the horizontal symptote y= -3 so put in x=3 in y=f(x^2) to get 9 and so at x=3 draw the new curve approaching -3

i know it complex but thats the way i do them

kool way and thanx for the help