DefiningTheta
Member
- Joined
- Aug 6, 2012
- Messages
- 124
- Gender
- Male
- HSC
- 2012
- Uni Grad
- 2018
I'm waiting for someone to do the last question of Q14...
awww dw mate, just hope the cut off for E4 falls to around 40 XDIdk about most of you..
but I found the test really hard -___- i couldnt do any of question 14 and i didn't get the probability right at ALL...
I got 1MC wrong, didn't know how to draw any of the graphs, got bits wrong here and there (ie. the newtons method & where that equation has a non-zero constant)
overal.. GG no more E4 for me, maybe not even an E3
I got an answer which corresponded with others, it was somewhere around 70-80 degreesFor 14biii), I actually found no angles that worked simultaneously for both. Question problem, or what? Test out your values of theta and see if they satisfy both equations
Seeing everyone found it easy I don't think soawww dw mate, just hope the cut off for E4 falls to around 40 XD
SHMNws m8 which one was that?
EDIT: Wrong question. I didn't get c(ii)what did youse do for Q.13) c) ii)
kill chem !seeing everyone found it easy i don't think so
i only got 40/70 for trials lmao and i'm feeling worse now than how i felt during trials... So my mark might be even lower
You have to take 0.3 away from C(T) to find a new polynomial/equation, which you then use to estimate, so you get 22.somethingEDIT: Wrong question. I didn't get c(ii)
arggh can't you read ?! C, not DEDIT: Wrong question. I didn't get c(ii)
you change the equation into Rcos(nt-whatever) = -5what did youse do for Q.13) c) ii)
Depends on the context. If it's obvious you're talking about simple harmonic motion I doubt it.Any chance of taking marks off for abbreviating "simple harmonic motion" to SHM?
You have to take 0.3 away from C(T) to find a new polynomial/equation, which you then use to estimate, so you get 22.something
Yeah thats what i got 22.7Any chance of taking marks off for abbreviating "simple harmonic motion" to SHM?
You have to take 0.3 away from C(T) to find a new polynomial/equation, which you then use to estimate, so you get 22.something