D Drewk Member Joined May 18, 2012 Messages 125 Gender Male HSC 2013 Nov 28, 2012 #1 Find the equation of the directrix of the following 3y^2=x (shouldn't it be x=1/3)?
Thief !! Joined Dec 18, 2010 Messages 561 Gender Male HSC 2013 Nov 28, 2012 #2 oops y^2 = x/3 a = 1/12 directrix at x = -1/12 Last edited: Nov 28, 2012
RealiseNothing what is that?It is Cowpea Joined Jul 10, 2011 Messages 4,591 Location Sydney Gender Male HSC 2013 Nov 28, 2012 #3 Thief said: a = 3/4 and as this is a sideways parabola with vertex (0,0) the directrix would be x = - 3/4 Click to expand... You sure about that lol.
Thief said: a = 3/4 and as this is a sideways parabola with vertex (0,0) the directrix would be x = - 3/4 Click to expand... You sure about that lol.
