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'Game Theory' on Coursera (Jan 7 - Feb 25) (1 Viewer)

OzKo

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Ended up getting 2/5 for the second problem set
 

seanieg89

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I feel posting here isn't violating my bostirement too badly. How is everyone finding the course? I got 9 for the first week but I had looked at similar things to that weeks material before. About to look at this weeks stuff.
 

OzKo

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I feel posting here isn't violating my bostirement too badly. How is everyone finding the course? I got 9 for the first week but I had looked at similar things to that weeks material before. About to look at this weeks stuff.
I'm finding it fairly challenging myself.
 

EpikHigh

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Is it too late to try this out? Didn't see this thread early but 'game theory' is something I guess I wanna learn a bit I dunno, probably because it was talked alot about in the TV series numb3rs =/.
 

seanieg89

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Is it too late to try this out? Didn't see this thread early but 'game theory' is something I guess I wanna learn a bit I dunno, probably because it was talked alot about in the TV series numb3rs =/.
Nope, sign up now. Its only been running for a week.
 

GoldyOrNugget

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Some cool 'challenge' maths questions I came up with:







And a compsci question too:

 
Last edited:

seanieg89

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Some cool 'challenge' maths questions I came up with:





And a compsci question too:

Sure about the first question? What about the game with payoff (0,0) for each strategy profile? That has exactly mn equilibria.
 

seanieg89

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Well the payoff corresponding to each action profile is a 2-vector of reals, saying that they are all distinct doesn't mean that they cannot still have one component equal, wherein lies the problem.

(2,1)|(1,1)
-----------
(2,2)|(1,2)

for instance has all action profiles as pure strat Nash equilibria. If you meant (as I am guessing you did) that every element of every payoff vector is distinct, then the key idea is that we cannot have two Nash equilibria in any row or column (as one would be preferred by the player whose action set give rise to the row or column).

And your colourings correspond to permutations of the set {1,2,...,n}, of which there are exactly n!.

The each colouring is equivalent to placing n rooks on an nxn chessboard in such a way that no two are attacking each other. From this observation iii) is clear.
 

Jinks

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Sorry to bump an old thread but I was just wondering how you all went/if you ended up completing it, and if so was it worth it?
 

OzKo

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Sorry to bump an old thread but I was just wondering how you all went/if you ended up completing it, and if so was it worth it?
Ended up stopping in the end because of laziness.

That being said, the course was well designed from what I saw of it.
 

nerdasdasd

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Would these courses be considered on your cv?
 

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