HeroicPandas
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This is a square, find x.
Those 3 lines have distances of 40m, 30m and 50m
Those 3 lines have distances of 40m, 30m and 50m
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A square (1 Viewer)
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HeroicPandas
Heroic!
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Aight cool
(I havent got the answer but i did a horizontal line cutting that point, then used pyfag, letting some unknown sides be x,y etc)
I took ages working this out. All my attempts seemed to end up with very high order polynomial equations.
Eventually I came up with a method that worked. I've attached the solution:
View attachment Three lines in a Square.pdf
Eventually I came up with a method that worked. I've attached the solution:
View attachment Three lines in a Square.pdf
RealiseNothing
what is that?It is Cowpea
Another way of getting rid of the answer 2 is to assume that a=2. Now the longest straight line that can be put inside a square is it's diagonal which measures a length of
Now
Last edited:
I use Word!! Plain ordinary Word.
HeroicPandas
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Great sol'n!
As I said, Word. Word has all the functionality built in for these diagrams.
It turns out that I was being a bit thick.
All that work was just a derivation of the cosine rule.
So I could have just used the cosine rule in each of the internal triangles to express cos alpha and sin alpha in terms of the other sides.
[Remembering to turn cos(90-alpha) into sin alpha.
All that work was just a derivation of the cosine rule.
So I could have just used the cosine rule in each of the internal triangles to express cos alpha and sin alpha in terms of the other sides.
[Remembering to turn cos(90-alpha) into sin alpha.
GoldyOrNugget
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Where is this functionality? Did you have to download any plugins?
No plugin is necessary.
In Word 2007, select Insert-Shapes-New Drawing Canvas.
A new 'Drawing Tools' Menu comes up, then just draw away using the tools in this menu.
The only plugin I have is the MathType equation editor which has no graphing capability.
As an aside to this question show that, if P is a point inside a square, and the distances of P from the vertices A, B and C are a, b and c respectively (where PC is the sided shared by both internal triangles), then the distance from P to the 4th vertex D is given by:
No Takers? It's not as hard as the original question.As an aside to this question show that, if P is a point inside a square, and the distances of P from the vertices A, B and C are a, b and c respectively (where PC is the sided shared by both internal triangles), then the distance from P to the 4th vertex D is given by: