Solve... (1 Viewer)

[Smile12345]

I've tried to solve this but I'm doing something wrong... Not sure how to type equations on here...

the question is to solve...

2-(1+x)/6=2x

 

[nerdasdasd]

Oops , I mean try find a common denominator .

 

[Carrotsticks]

Bring the 6 over to the rhs and then solve it.

This is assuming the 6 is the denominator to all of the LHS.

I have a feeling OP's question is more like this:

 

[Smile12345]

It ends up as x=11/3.

What about x^2 -9 / 3 - x ???? Xsquared - 9 divided by 3 - x...

 

[Smile12345]

Yes, that is what it looks like. How did you get the equation?

 

[Carrotsticks]

Yes, that is what it looks like. How did you get the equation?

I used a typesetting called LaTeX.

http://community.boredofstudies.org/showthread.php?t=234262

 

[Sy123]

Yes, that is what it looks like. How did you get the equation?

By making a common denominator.



Then multiplying 6 to both sides of the equation, to eliminate the fraction (or cross multiply, same thing).



Expand the minus in:



Collect like terms:





==========

For the second one, it is not an equation, just an expression.

By recognising difference between two squares, using the formula: which can be verified by expanding the RHS



Then, by factoring out a minus from the bottom



Then cancelling out, the (x-3) term



By

 

[omgiloverice]

edit: nevermind...

 

[Smile12345]

I used a typesetting called LaTeX.

http://community.boredofstudies.org/showthread.php?t=234262

Thanks. Just what I was after...

 

[Smile12345]

Thanks heaps Sy123... You've explained it very clearly and I understand it 100% now!!

 

[Smile12345]

Just experimenting with LaTeX

(2+\sqrt{3})^2

( 2+/sqrt{3})

 

[Carrotsticks]

Just experimenting with LaTeX

(2+\sqrt{3})^2

( 2+/sqrt{3})

You forgot the '[tex ]' and the '[ /tex]' on either side of your code =)

 

[Smile12345]

I'm boxed! So how should it look???

 

[Carrotsticks]

['tex](2+\sqrt{3})^2[/tex']

But without the ' symbols.

 

[Smile12345]

Thanks heaps...

I've tried this way (in word, I inserted an equation)... Does the below make sense?

Example... Sketch the curves showing the main features - y=√(1-x^2 )... This would be semicircle on top of the xaxis....

 

[nerdasdasd]

 

[Smile12345]

Thanks. Don't know why I can't see your pic but I've got it...