Perpendicular Distance Please (1 Viewer)

[Smile12345]

Could someone please confirm that...

The perpendicular distance between the line y=2x +5 and the point (1,-3) is ... 10root5 / 5

The answers say something different so I want to make sure I am correct...

Thanks for your help in advance...Sorry I originally had the wrong point...

 

[MissyL]

Did you have the absolute value for the numerator?

 

[Carrotsticks]

Could someone please confirm that...

The perpendicular distance between the line y=2x +5 and the point (1,3) is ... 10root5 / 5

The answers say something different so I want to make sure I am correct...

Thanks for your help in advance...

EDIT: Please ignore this. I quoted the Perpendicular Distance Formula incorrectly ='(

 

[Smile12345]

Sorry it would help if I had the question correctly... The point should be (1, -3)

Thanks for your help carrotsticks. I suspect that's what the answers had done. A 3 instead of -3!!

 

[SharkeyBoy]

d = (|2+3+5| / √10 )
= 10/√10
= √10

 

[Smile12345]

Thanks SharkeyBoy...


Isn't the bottom meant to be the square root of -1^2 + 2^2?? In the formula it's asquared + bsquared??

 

[Carrotsticks]

Please forgive me, I mis-quoted the formula.

The correct solution is as follows. The perpendicular distance between the point (1,-3) and the line 2x-y+5=0 is...

 

[Smile12345]

Please forgive me, I mis-quoted the formula.

The correct solution is as follows. The perpendicular distance between the point (1,-3) and the line 2x-y+5=0 is...

I will... I misquoted the point to begin with!! Glad to know I did have the right formula! Thanks...

 

[SharkeyBoy]

haha yeah, sorry it is 2√5 , i was just copying carrotsticks and changing the 3, my bad

 

[Smile12345]

Hehe! No worries, quite easy to do.....