Help with differentiation question (1 Viewer)

[girlworld_club]

correct. i don't understand why the probability of choosing a women in the first group is 1/2. i thought that there was 21 people in total at the party, and there are a total of 9 people in group one. so she has a 9/21 chance of picking someone in group 1, since group 1 and group 2 are mixed together in a room?

it makes sense since there are more people in group 1 so there is a greater chance of picking someone from group 1 in comparison to group 2. not a half chance of picking someone in group 1 or group 2. if they were separated into two rooms then it would make sense, but not alltogether.

 

[HeroicPandas]

"There are two groups of people *at a part*..."
*at a park?
*apart?

I'm assuming its "There are 2 groups of people APART..."

 

[Kostie100]

keep in mind, i do extra steps so u can see the light




FOR THE BOLDED PART - can u show me ur working out?

So i see you have used product rule? Can you not just move the 2 to the front and have to find d/dx of x^2 + 32 loge (5-x) ?

 

[girlworld_club]

it'a actually at a party. so..what are your thoughts now?

 

[Drongoski]

So i see you have used product rule? Can you not just move the 2 to the front and have to find d/dx of x^2 + 32 loge (5-x) ?

Not product rule - but the Chain Rule.

 

[HeroicPandas]

So i see you have used product rule? Can you not just move the 2 to the front and have to find d/dx of x^2 + 32 loge (5-x) ?

ln(5-x)^2 = [ln(5-x)]^2

ln(5-x)^2 =/= 2ln(5-x)

However,

ln[(5-x)^2] = 2ln(5-x)

Importantly,

The power must be within the logarithm, for u to apply that rule:

it'a actually at a party. so..what are your thoughts now?

just to confirm, are my answers ALL correct?

"i ) find the probability that minh approaches a person in the first group and then selects a women. "

approaches the first group

that means groups must be separate

 

[girlworld_club]

approached a person in the first group...the wording is a bit ambig..you could still approach a person in the first group if they are together.

 

[Kostie100]

ln(5-x)^2 = [ln(5-x)]^2

ln(5-x)^2 =/= 2ln(5-x)

However,

ln[(5-x)^2] = 2ln(5-x)

Importantly,

The power must be within the logarithm, for u to apply that rule:

Thank you very much for the great explanation, btw I meant the chain rule in my original post (wasn't thinking).

 

[HeroicPandas]

approached a person in the first group...the wording is a bit ambig..you could still approach a person in the first group if they are together.

"minh approaches a person in the first group and then selects a women. "

So minh chooses that particular group and then starts to pick a person

Thank you very much for the great explanation, btw I meant the chain rule in my original post (wasn't thinking).

no problems