Noob question (1 Viewer)

[nexusbrah]

Calculate the max height

Just started year 12 phys

I feel as if in the question is missing information

 

[superSAIyan2]

motion of proectile is symmetrcal, so time of max height is 3.75s and the projectile's horizontal displacement is 600m
also note y velocity at max height is 0,
i got an answer of 68.91m

 

[QZP]

Insufficient information...

 

[Fizzy_Cyst]

You have plenty of info

time to max height (i.e., Vy = 0) = 3.75s (half of total time of flight) , assuming it is on Earth, you can find Uy and hence you can find delta_Y

\o/

 

[nexusbrah]

motion of proectile is symmetrcal, so time of max height is 3.75s and the projectile's horizontal displacement is 600m
also note y velocity at max height is 0,
i got an answer of 68.91m

You have plenty of info

time to max height (i.e., Vy = 0) = 3.75s (half of total time of flight) , assuming it is on Earth, you can find Uy and hence you can find delta_Y

\o/

Thanks alot!

Got the answer