Help with differentiation of exponentials (1 Viewer)

[Prawnchip]

Find y"
given that y = (e^2x + 1)^7

help me i end up with this really funky answer

many thanks

 

[rumbleroar]

use chain rule, and treat the stuff inside as "u" and dash it as you would when you have (x+1)^7 (this is for y')

and then you repeat, but with y" you should use product rule.

 

[rumbleroar]

I think you should get 14e^2x multiplied by (e^2x+1)^6 (could be wrong, bit rusty on exponentials) EDIT: <-- for y'

sorry, I misread and didn't realise it was y"

but I got y" = 28e^2x(e^2x+1)^5[(e^2x+1)+6e^2x]

 

[asianese]

That's correct -

 

[Prawnchip]

I think you should get 14e^2x multiplied by (e^2x+1)^6 (could be wrong, bit rusty on exponentials) EDIT: <-- for y'

sorry, I misread and didn't realise it was y"

but I got y" = 28e^2x(e^2x+1)^5[(e^2x+1)+6e^2x]

thanks! many many thanks amigo