K kasser New Member Joined Jun 7, 2014 Messages 18 Gender Undisclosed HSC N/A Jun 19, 2014 #1 AB is a diameter of a circle and CD is a chord drawn perpendicular to A cutting it at X. Prove that CX ^2 = AX.XB
AB is a diameter of a circle and CD is a chord drawn perpendicular to A cutting it at X. Prove that CX ^2 = AX.XB
B braintic Well-Known Member Joined Jan 20, 2011 Messages 2,137 Gender Undisclosed HSC N/A Jun 19, 2014 #2 This is straight Intersecting Chords Theorem, where CX=DX because a radius perpendicular to a chord bisects the chord.
This is straight Intersecting Chords Theorem, where CX=DX because a radius perpendicular to a chord bisects the chord.
F Fiction Active Member Joined Apr 19, 2014 Messages 773 Gender Undisclosed HSC 2015 Jun 19, 2014 #3 Isn't this property 16...?
B braintic Well-Known Member Joined Jan 20, 2011 Messages 2,137 Gender Undisclosed HSC N/A Jun 20, 2014 #4 Fiction said: Isn't this property 16...? Click to expand... How is anyone meant to know what you mean by property 16? Where do you get that number from?
Fiction said: Isn't this property 16...? Click to expand... How is anyone meant to know what you mean by property 16? Where do you get that number from?
seanieg89 Well-Known Member Joined Aug 8, 2006 Messages 2,662 Gender Male HSC 2007 Jun 20, 2014 #5 If you want to prove this property, it comes out quickly from considering similar triangles.
