• Congratulations to the Class of 2024 on your results!
    Let us know how you went here
    Got a question about your uni preferences? Ask us here

Linear functions (1 Viewer)

Joshmosh2

Member
Joined
Mar 30, 2014
Messages
181
Gender
Male
HSC
2015
If I have the origin, (0,0) and a random point along the y-axis, for example A (0,2) and am given point, for example P (-3,-1) how can I make an equation for line PB if B is perpendicular to OA?
In simpler terms, I want to find the perpendicular gradient of OA
 

rumbleroar

Survivor of the HSC
Joined
Nov 30, 2011
Messages
2,271
Gender
Female
HSC
2014
1. Find gradient of OA (simple rise-run formula will do)
2. Use the fact that when any two perpendicular gradients are multiplied, they equal -1. i.e. m_1 x m_2 = -1 and use that to figure out the value of the gradient of PB
 

Joshmosh2

Member
Joined
Mar 30, 2014
Messages
181
Gender
Male
HSC
2015
1. Find gradient of OA (simple rise-run formula will do)
2. Use the fact that when any two perpendicular gradients are multiplied, they equal -1. i.e. m_1 x m_2 = -1 and use that to figure out the value of the gradient of PB
Hmm am I missing something? If you do the rise / run = 2/0 = undefined
 

D94

New Member
Joined
Oct 5, 2011
Messages
4,423
Gender
Male
HSC
N/A
Think about what OA looks like. It's just a vertical straight line from the origin. So any line that is perpendicular to that must be a horizontal straight line, and in this case, it passes through point P.
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top