You get a different value when you integrate x+1 as (x+1)^1 ? (1 Viewer)

[sadpwner]

If i integrate x+1 individually then i get x^2 /2 +x +c, but if I integrate it as (x+1)^1 then I get x^2 /2 +x +1/2 + c?

 

[Trebla]

If i integrate x+1 individually then i get x^2 /2 +x +c, but if I integrate it as (x+1)^1 then I get x^2 /2 +x +1/2 + c?

1/2 + c is an arbitrary constant as is c so they are effectively equivalent (you can check by differentiating both answers)