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Hard Vectors Q (1 Viewer)

Thread starter mreditor16
Start date Mar 22, 2015

I

InteGrand

Well-Known Member

#21

mreditor16 said:
Can anyone identify the flaw in my vectors?

AB = (-18 sin (18 degrees), + 18 cos (18 degrees))

BC = (25 sin (36 degrees), + 25 cos (36 degrees))

CD = (+20 cos (18 degrees), - 20 sin (18 degrees))

DF = (-15 sin (25 degrees), - 15 cos (25 degrees))

They look right to me.

mreditor16

Well-Known Member

#22

oh oops figured it out. thanks so so so much for your help, Photastic and Integrand

P

photastic

Well-Known Member

#23

mreditor16 said:
oh oops figured it out. thanks so so so much for your help, Photastic and Integrand

How do you find the angle again??

mreditor16

Well-Known Member

#24

photastic said:
How do you find the angle again??

90 degrees - tan inverse of yAF / xAF

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