S SammyT123 Active Member Joined Nov 16, 2014 Messages 360 Gender Male HSC 2016 Apr 14, 2015 #1 12. If a>b and b is not equal to zero, prove: a) -a<-b b) ab^2 > b^3 I understand these questions (common sense ) but how exactly would I do an official proof for them? Thanks -SammyT
12. If a>b and b is not equal to zero, prove: a) -a<-b b) ab^2 > b^3 I understand these questions (common sense ) but how exactly would I do an official proof for them? Thanks -SammyT
I InteGrand Well-Known Member Joined Dec 11, 2014 Messages 6,109 Gender Male HSC N/A Apr 14, 2015 #2 SammyT123 said: 12. If a>b and b is not equal to zero, prove: a) -a<-b b) ab^2 > b^3 I understand these questions (common sense ) but how exactly would I do an official proof for them? Thanks -SammyT Click to expand... Given: a) Add to both sides of the above, and the desired inequality is reached. b) (you can multiply an inequality through by a positive number, which is)
SammyT123 said: 12. If a>b and b is not equal to zero, prove: a) -a<-b b) ab^2 > b^3 I understand these questions (common sense ) but how exactly would I do an official proof for them? Thanks -SammyT Click to expand... Given: a) Add to both sides of the above, and the desired inequality is reached. b) (you can multiply an inequality through by a positive number, which is)
S SammyT123 Active Member Joined Nov 16, 2014 Messages 360 Gender Male HSC 2016 Apr 14, 2015 #3 InteGrand said: Given: a) Add to both sides of the above, and the desired inequality is reached. b) (you can multiply an inequality through by a positive number, which is) Click to expand... That's all? That was my answer but it didn't seem right that a question would be this simple Sent from my iPhone using Tapatalk
InteGrand said: Given: a) Add to both sides of the above, and the desired inequality is reached. b) (you can multiply an inequality through by a positive number, which is) Click to expand... That's all? That was my answer but it didn't seem right that a question would be this simple Sent from my iPhone using Tapatalk
B braintic Well-Known Member Joined Jan 20, 2011 Messages 2,137 Gender Undisclosed HSC N/A Apr 14, 2015 #4 SammyT123 said: That's all? That was my answer but it didn't seem right that a question would be this simple Sent from my iPhone using Tapatalk Click to expand... Alternatively: ab² - b³ = b²(a-b) > 0 since a>b & b²>0 ab² > b³
SammyT123 said: That's all? That was my answer but it didn't seem right that a question would be this simple Sent from my iPhone using Tapatalk Click to expand... Alternatively: ab² - b³ = b²(a-b) > 0 since a>b & b²>0 ab² > b³
S SammyT123 Active Member Joined Nov 16, 2014 Messages 360 Gender Male HSC 2016 Apr 14, 2015 #5 braintic said: Alternatively: ab² - b³ = b²(a-b) > 0 since a>b & b²>0 ab² > b³ Click to expand... Thanks Sent from my iPhone using Tapatalk
braintic said: Alternatively: ab² - b³ = b²(a-b) > 0 since a>b & b²>0 ab² > b³ Click to expand... Thanks Sent from my iPhone using Tapatalk