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2 unit maths help please ! (1 Viewer)
- Thread starter abdullion
- Start date
im assuming that astroman read the question another way, but I'm reading it as 4^a + (3x4^a) = 8
so first factorise LHS
4^a (1 + 3) = 8
4^a (4) = 8
divide both sides by 4
4^a = 2
LHS 4^a is also equal to 2^2a, so
2^2a = 2
from direct comparison
2a = 1
a = 1/2 hope that helps
so first factorise LHS
4^a (1 + 3) = 8
4^a (4) = 8
divide both sides by 4
4^a = 2
LHS 4^a is also equal to 2^2a, so
2^2a = 2
from direct comparison
2a = 1
a = 1/2 hope that helps
An attempt was made
VBN's answer is spot on though
(It's probably the best way to approach the question as it is considered an equation reducible to a quadratic)