Algebraic Proof :) (1 Viewer)

[Energised]

Hello,

Can someone please help me with this question:

If , show that .

Thank you very much.

Energised

 

[Shadowdude]

Hello,

Can someone please help me with this question:

If , show that .

Thank you very much.

Energised

But

 

[Shadowdude]

I thought:


And then. . . Can you simplify this side to = the other or?

Uhh you made an algebra mistake when substituting in... because that simplification isn't right

Try on paper

 

[Energised]

Sorry changed now. . .

So did you multiply each term by x to get to the next step??

Thanks.

 

[Shadowdude]

Sorry changed now. . .

So did you multiply each term by x to get to the next step??

Thanks.

Yeah, I multiplied by \frac{x}{x}

Also your edit's numerator is still wrong... I'd suggest you go from my working and figure out the intermediate steps to get what I have exactly

 

[Energised]

Yeah, I multiplied by \frac{x}{x}

Also your edit's numerator is still wrong... I'd suggest you go from my working and figure out the intermediate steps to get what I have exactly

Sorry, getting a bit mixed up trying to use latex!!

I can get how you got to the next step... Now...

 

[Energised]

How do you get to the last line??

Also how about this q: (I just can't get the last part)

The graph of is the line y= x +14 (I think) with a discontinuity at the point _________?.

Thanks.

 

[VBN2470]

You have . But so the point of discontinuity occurs at .

 

[Shadowdude]

How do you get to the last line??

Also how about this q: (I just can't get the last part)

The graph of is the line y= x +14 (I think) with a discontinuity at the point _________?.

Thanks.

You mean the one starting with "But"?

It's a separate thing. You simplify the thing on the previous line, and then you should see the link.

 

[Energised]

You have . But so the point of discontinuity occurs at .

Ah, thanks heaps. That makes sense. And the reason that x can't = 1, is because the bottom of the fraction cannot = 0, am I right.

Thanks.

 

[Energised]

You mean the one starting with "But"?

It's a separate thing. You simplify the thing on the previous line, and then you should see the link.

Thanks I understand, (you just simplify again, then multiply each term by x.

How's the x can't = 0 on the end impact?

 

[panda15]

Thanks I understand, (you just simplify again, then multiply each term by x.

How's the x can't = 0 on the end impact?

Because g(x) is defined at x=0, but g(1/x) is not because 1/x is not defined at x=0, so g(x) does not equal g(1/x) at x=0.

 

[Energised]

Because g(x) is defined at x=0, but g(1/x) is not because 1/x is not defined at x=0, so g(x) does not equal g(1/x) at x=0.

Thank you for your explanation, yes, that makes sense now.