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quick easy question (1 Viewer)

Thread starter Green Yoda
Start date Jun 4, 2015

Green Yoda

Hi Φ

#1

Screenshot 2015-06-04 at 19.19.51.png

Factorise fully

I

InteGrand

Well-Known Member

#2

Rathin said:
View attachment 32100
Factorise fully

http://www.artofproblemsolving.com/wiki/index.php/Sophie_Germain_Identity

leehuan

Well-Known Member

#3

${ a }^{ 4 }+4{ b }^{ 4 }\\ =\left( { a }^{ 4 }+4{ a }^{ 2 }{ b }^{ 2 }+4{ b }^{ 4 } \right) -4{ a }^{ 2 }b^{ 2 }\\ ={ \left( { a }^{ 2 }+2b^{ 2 } \right) }^{ 2 }-{ \left( 2ab \right) }^{ 2 }\\ =\left( { a }^{ 2 }+2{ b }^{ 2 }+2ab \right) \left( { a }^{ 2 }+2{ b }^{ 2 }-2ab \right) $ Fully factorised over $\mathbb R$

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