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Green Yoda

Green Yoda

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Screenshot 2015-08-15 at 12.05.47.png

I have got AC as root 3 but I have no idea what to do from then.
 
Green Yoda

Green Yoda

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Yup got it, So what i did was first find AC by Cos 30 = AC/2 which is x = cos 30 x 2 = √ 3/2 x 2, therefore AC= √ 3 .
Now I found DC by sin 30 = DC/2, there fore DC = sin 30 x 2 which is 1/2 x so therefore DC = 1
As angles D and C are same so that means DC and BC are same so therefore BC = 1.
Now to find BD, AC-BC which is √ 3 -1.
Is this the correct method?
 
I

InteGrand

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Rathin said:
Yup got it, So what i did was first find AC by Cos 30 = AC/2 which is x = cos 30 x 2 = √ 3/2 x 2, therefore AC= √ 3 .
Now I found DC by sin 30 = DC/2, there fore DC = sin 30 x 2 which is 1/2 x so therefore DC = 1
As angles D and C are same so that means DC and BC are same so therefore BC = 1.
Now to find BD, AC-BC which is √ 3 -1.
Is this the correct method?
Click to expand...
Yes that is correct.
 
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