Trials question (1 Viewer)

[BlueGas]

I need someone to explain each of the answers, what does it mean if the particle is moving towards the origin? Doesn't it mean if it's moving towards (0,0)? But the particle in the graph isn't, so why can't that be an answer?

 

[InteGrand]

I need someone to explain each of the answers, what does it mean if the particle is moving towards the origin? Doesn't it mean if it's moving towards (0,0)? But the particle in the graph isn't, so why can't that be an answer?

Moving towards origin means moving towards its 0 position on its line of motion (the real number line). A 2D location (0,0) is irrelevant because the motion is 1D for the particle. The graph isn't a picture of the particle's path, it's a picture of its position on the x-axis vs. time (the particle is just moving along the x-axis of the plane (one-dimensional motion), aka the real number line; this is UNRELATED to the horizontal axis of this graph).

 

[InteGrand]

 

[InteGrand]

 

[InteGrand]

 

[BlueGas]

So basically if a particle meets the x-axis means it has met the origin?

 

[InteGrand]

So basically if a particle meets the x-axis means it has met the origin?

If it meets the HORIZONTAL axis of that graph, yes. Avoid saying "x-axis" for that graph unless you mean the vertical axis, because the horizontal axis is actually called the t-axis here, and the vertical axis is the x-axis, due to the names of the variables on each axis.

 

[BlueGas]

If it meets the HORIZONTAL axis of that graph, yes. Avoid saying "x-axis" for that graph unless you mean the vertical axis, because the horizontal axis is actually called the t-axis here, and the vertical axis is the x-axis, due to the names of the variables on each axis.

Oh okay, yep I meant the t-axis.

 

[InteGrand]

Actually, its wrong to say "it" meets the t-axis, because it isn't moving along that graph. That graph is NOT a picture of its path. Rather, say that the particle is at the origin at any time that graph hits the t-axis.