Probability Question (1 Viewer)

Green Yoda · Oct 18, 2015

I need help on this Hsc 2014 MC Question:

kawaiipotato · Oct 18, 2015

$Use complementary probability$

$$P(no-one winning) + P(at least 1 person winning) $ = 1$

$$P(no-one winning)$ = \frac{3}{4} * \frac{5}{6} * \frac{3}{5}$

$= \frac{3}{8}$

$$ Hence, P(at least 1 win) $ = 1- \frac{3}{8} = \frac{5}{8}$

$\Rightarrow $ D $$

calamebe · Oct 18, 2015

Bit early to be doing HSC questions haha

astroman · Oct 18, 2015

calamebe said:
Bit early to be doing HSC questions haha

It's never to early to learn.

Green Yoda · Oct 18, 2015

calamebe said:
Bit early to be doing HSC questions haha

Well the teacher said.."The textbook is shit" and "Do hsc probability questions from 2008 onwards for hw".
Tbh most of the questions are pretty easy

photastic · Oct 18, 2015

Rathin said:
Well the teacher said.."The textbook is shit" and "Do hsc probability questions from 2008 onwards for hw".
Tbh most of the questions are pretty easy

Wanna try the questions from the marathons?

Green Yoda · Oct 18, 2015

photastic said:
Wanna try the questions from the marathons?

2u marathon?

photastic · Oct 18, 2015

Rathin said:
2u marathon?

Yep or any of the levels tbh.

Green Yoda · Oct 18, 2015

photastic said:
Yep or any of the levels tbh.

I shall try. probs gonna get rekt but whateves

kawaiipotato · Oct 18, 2015

Rathin said:
2u marathon?

Also the MX2 Permutation marathon

Speed6 · Oct 18, 2015

kawaiipotato said:
Also the MX2 Permutation marathon

Relax, your gonna make his GCS plummet to 3.

(Some people may get what I mean lol)

Probability Question (1 Viewer)

Green Yoda

Hi Φ

kawaiipotato

Well-Known Member

calamebe

Active Member

astroman

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Green Yoda

Hi Φ

photastic

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Green Yoda

Hi Φ

photastic

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Green Yoda

Hi Φ

kawaiipotato

Well-Known Member

Speed6

Retired '16

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