Inverse trig integration (1 Viewer)

[InteGrand]

Would the same principle apply for another question like "find the area btwn y=sin^-1 x/2, x=1 and x=2 and the x-axis?

Yeah you can. If you draw a sketch, you should be able to identify the relevant rectangle and relevant "red area" to subtract from the rectangle area. The "red area" will be able to be computed similarly to above (integrating a function of y between y limits).

 

[eyeseeyou]

Okay I need help

Find the area of the bounded byt the curve y=sin^-1 x, the x axis and the line x=1 and x=-1

I did area =integral from pi/2 to -pi/2 x dy
integral of pi/2 and -pi/2 siny dy
-cosy (borders from pi/2 to -pi/2)
=0

What am I doing wrong?

 

[Paradoxica]

Okay I need help

Find the area of the bounded byt the curve y=sin^-1 x, the x axis and the line x=1 and x=-1

I did area =integral from pi/2 to -pi/2 x dy
integral of pi/2 and -pi/2 siny dy
-cosy (borders from pi/2 to -pi/2)
=0

What am I doing wrong?

The area is negative on the left and positive on the right, and being an odd function, it cancels.

They wanted the unsigned area, so you will be finding twice the area bounded by the curve from 0 to 1.