HSC 2017 MX2 Marathon (archive) (1 Viewer)

Status
Not open for further replies.

leehuan

Well-Known Member
Joined
May 31, 2014
Messages
5,805
Gender
Male
HSC
2015
Re: HSC 2017 4U Marathon

Had to make sure lol
In sciences a LINE of best fit can be a linear line of best fit or a curve of best fit
Actually, I don't even know why a line of best fit can be a curve. I would just call a curve of best fit its own seperate thing. (Polynomial of best fit, blah blah)
 

seanieg89

Well-Known Member
Joined
Aug 8, 2006
Messages
2,662
Gender
Male
HSC
2007
Re: HSC 2017 4U Marathon

Had to make sure lol
In sciences a LINE of best fit can be a linear line of best fit or a curve of best fit
That's just hazy high school science definitions. There are various precise definitions of lines/curves of best fit (regression analysis, interpolating polynomials etc), and whenever such an object is named a line it is definitely a line in the usual sense of the word (at least as far as I have seen).
 

mini8658

New Member
Joined
Sep 25, 2015
Messages
21
Gender
Undisclosed
HSC
N/A
Re: HSC 2017 4U Marathon

Is there a way to expand it so the cis2kpi/5's cancel out, leaving only the z^5-1?
 

Green Yoda

Hi Φ
Joined
Mar 28, 2015
Messages
2,859
Gender
Male
HSC
2017
Re: HSC 2017 4U Marathon

Quick question: When we are finding the roots of unity (or any complex number) and leaving it in mod-arg form do we have to change the argument to the principle range or just leave it as it as (e.g. for k=5 arg = 15pi/8). The answers in past papers leave it as it is...so not sure what to do.
 

calamebe

Active Member
Joined
Mar 19, 2015
Messages
462
Gender
Male
HSC
2017
Re: HSC 2017 4U Marathon

Quick question: When we are finding the roots of unity (or any complex number) and leaving it in mod-arg form do we have to change the argument to the principle range or just leave it as it as (e.g. for k=5 arg = 15pi/8). The answers in past papers leave it as it is...so not sure what to do.
I always converted it to the principle range, technically you'd be right, but it's better to be safe.
 

pikachu975

Premium Member
Joined
May 31, 2015
Messages
2,739
Location
NSW
Gender
Male
HSC
2017
Re: HSC 2017 4U Marathon

Quick question: When we are finding the roots of unity (or any complex number) and leaving it in mod-arg form do we have to change the argument to the principle range or just leave it as it as (e.g. for k=5 arg = 15pi/8). The answers in past papers leave it as it is...so not sure what to do.
I like to use -2, -1, 0, 1, 2 instead of 0, 1, 2, 3, 4 because it'll always give you arguments in the principal argument range.

Just a side note it's principal argument not principle
 

InteGrand

Well-Known Member
Joined
Dec 11, 2014
Messages
6,109
Gender
Male
HSC
N/A
Re: HSC 2017 4U Marathon






 
Last edited:

integral95

Well-Known Member
Joined
Dec 16, 2012
Messages
779
Gender
Male
HSC
2013
Re: HSC 2017 4U Marathon

This is probably a vague explanation but...


In the case where both roots are real.
The sum of roots = -b/a, which is negative if a,b are either both positive or both negative. This implies that at least one of the roots is negative.
Product of roots = c/a, if the roots are both negative, then the product must be positive therefore a,c must be both positive or both negative.

If the roots are complex, they must be in conjugate pairs due to real coefficients, this means that the real parts must be the same.
So if the real part is negative, then the sum of roots must be negative, and the product of roots must be positive.
 

Kingom

Member
Joined
Apr 25, 2015
Messages
49
Gender
Male
HSC
2019
Re: HSC 2017 4U Marathon

here's a nice binomial followed by a harder binomial
133.PNG
134.PNG
 

stupid_girl

Active Member
Joined
Dec 6, 2009
Messages
221
Gender
Undisclosed
HSC
N/A
Re: HSC 2017 MX2 Marathon

This geometry question doesn't involve any advanced knowledge but requires a bit of creativity.:tongue:

ABCD is a quadrilateral with three equal sides AB,BC and CD. Show that the mid-point of AD lies on a circle with diameter BC if and only if the area of ABCD is a quarter of the product of its diagonals.
 

frog1944

Member
Joined
Apr 9, 2016
Messages
210
Gender
Undisclosed
HSC
2017
Re: HSC 2017 MX2 Marathon

A question posted in the 2016 MX2 marathon by Paradoxica that wasn't answered:
 

si2136

Well-Known Member
Joined
Jul 19, 2014
Messages
1,370
Gender
Undisclosed
HSC
N/A
Re: HSC 2017 MX2 Marathon

A question posted in the 2016 MX2 marathon by Paradoxica that wasn't answered:
It approaches infinity.

lim x--> 0, sin x / (1-cos x)

= lim x--> 0 (1+cos x) / sin x

Apply l'hopital, sin^2 x, sin^4 x, all approach infinity.

Therefore the limit approaches infinity.

Could someone check my answer please? Thanks.
 

InteGrand

Well-Known Member
Joined
Dec 11, 2014
Messages
6,109
Gender
Male
HSC
N/A
Re: HSC 2017 MX2 Marathon

It approaches infinity.

lim x--> 0, sin x / (1-cos x)

= lim x--> 0 (1+cos x) / sin x

Apply l'hopital, sin^2 x, sin^4 x, all approach infinity.

Therefore the limit approaches infinity.

Could someone check my answer please? Thanks.
 

seanieg89

Well-Known Member
Joined
Aug 8, 2006
Messages
2,662
Gender
Male
HSC
2007
Re: HSC 2017 MX2 Marathon

Suppose you have n points on a circle such that no three distinct chords coincide at any single point.

How many regions do the nC2 chords divide the interior of the circle into?

(You don't have to provide rigorous proof for this question if you can guess the answer correctly).
 

dan964

what
Joined
Jun 3, 2014
Messages
3,479
Location
South of here
Gender
Male
HSC
2014
Uni Grad
2019
Re: HSC 2017 MX2 Marathon

Suppose you have n points on a circle such that no three distinct chords coincide at any single point.

How many regions do the nC2 chords divide the interior of the circle into?

(You don't have to provide rigorous proof for this question if you can guess the answer correctly).
2m where m is the number of chords. (2*nC2??)

Sorry thats not right, hold on.
 

Sy123

This too shall pass
Joined
Nov 6, 2011
Messages
3,730
Gender
Male
HSC
2013
Re: HSC 2017 MX2 Marathon

Part (b) is a little long and requires good understanding of the problem, so keep that in mind






---------------------------------









---------------------------------

---------------------------------
 
Last edited:

Paradoxica

-insert title here-
Joined
Jun 19, 2014
Messages
2,556
Location
Outside reality
Gender
Male
HSC
2016
Re: HSC 2017 MX2 Marathon

Suppose you have n points on a circle such that no three distinct chords coincide at any single point.

How many regions do the nC2 chords divide the interior of the circle into?

(You don't have to provide rigorous proof for this question if you can guess the answer correctly).
something along the lines of the sum of three binomial coefficients of even lower argument...

I'll leave the details to the interested reader...
 

dan964

what
Joined
Jun 3, 2014
Messages
3,479
Location
South of here
Gender
Male
HSC
2014
Uni Grad
2019
Re: HSC 2017 MX2 Marathon

Just a reminder this thread is mainly for Q1-15 material, and should be accessible to all Ext 2 students, not just the really talented ones.

I have moved the Lagrange multiplier & IMO question to the Advanced Marathon thread here...
http://community.boredofstudies.org...-2/360463/hsc-2017-mx2-marathon-advanced.html

If you have questions for help not related to questions posted here, it is advisable to post a separate thread rather than posting here in the marathon thread thanks. Although feel free to post a question here of course...
I have moved some of those also out of this thread.

here is another question to attempt
abbotsleigh20034u_q7b.PNG
 
Last edited:
Status
Not open for further replies.

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top