For the first one, multiply top and bottom of the LHS by tan(x). This makes the numerator become tan(x) + 1, and the denominator is tan(x)(1 + tan(x)), so the fraction becomes 1/(tan(x)) = cot(x).
For the second one, multiply top and bottom of the LHS by 1 – sin(α), and remember the difference of two squares and that 1 – sin2(α) = cos2(α).
For the first one, multiply top and bottom of the LHS by tan(x). This makes the numerator become tan(x) + 1, and the denominator is tan(x)(1 + tan(x)), so the fraction becomes 1/(tan(x)) = cot(x).
For the second one, multiply top and bottom of the LHS by 1 – sin(α), and remember the difference of two squares and that 1 – sin2(α) = cos2(α).