A diagonal of a rhombus with the size 9 cm makes a angle of 16 degrees with the side Find the length of the diagonalso
Let the length of diagonal AC be
x cm.
AD = CD = 9cm (equal sides of rhombus ABCD)
∠DCB = 2*16° = 32° (diagonal AC bisects vertex ∠DCB through which it passes)
AD||BC (opposite sides of rhombus ABCD parallel)
Therefore, ∠D + ∠DCB = 180° (co-interior angles supplementary on AD||BC)
Therefore, ∠D = 180° - 32° = 148°
Now,
x2 = 9
2 + 9
2 - 2*9*9cos148° (cosine rule)
x2 = 81*2 - 162cos148°
x2 = 299.3837916
x = 17.30271053cm
Therefore,
x = 17.30cm (2 dec. pl.)