Yeah, it's pretty weird but it was in my school's past paper, I think they putted the question, to maybe prepare us for the HSC. :Well when you solve the equation you get the roots x=2/3 and x=1
Then just let one of the roots be alpha and the other be beta. Then sub it into part a). I think part a) is a bit weird since you can't tell which root will be alpha and which will be beta since you are multiplying each one by a different number. If you typed part a) correctly, then you would have two different solutions.
For b), just use the square of the product of roots formula (i.e. just multiply the square of 2/3 and 1 which gives 4/9)
I'm pretty sure there's a typo in the question they're never gonna ask 2alpha + 3beta I bet they were meant to have 2alpha + 2beta or 3alpha + 3beta or something to apply -b/aYeah, it's pretty weird but it was in my school's past paper, I think they putted the question, to maybe prepare us for the HSC. :
I checked the question again it still say 2alpha+ 3beta, but I think you are right it Must be a typo, I'll ask my teacher tomorrow because our yearly are going on and tomorrow is mathematics, so it's urgent for me to ask them this question before it's too late.I'm pretty sure there's a typo in the question they're never gonna ask 2alpha + 3beta I bet they were meant to have 2alpha + 2beta or 3alpha + 3beta or something to apply -b/a