Maths Help (1 Viewer)

Farhanthestudent005 · Jun 22, 2022

How do I do these ones?

Drongoski · Jun 22, 2022

Farhanthestudent005 said:
View attachment 35848

View attachment 35847
How do I do these ones?

2.

$\frac {dy}{dx} = 1 - \frac {y}{3} = \frac {3 - y}{3}\\ \\ \therefore \frac {dy}{3-y} = \frac {dx}{3}\\ \\ \therefore \int \cdots dy = \int \cdots dx \\ \\ \therefore -ln |3-y| = \frac {x}{3} + C \\ \\ x = 2 \implies y = 4 \implies -ln|3 - 4| = \frac {2}{3} + C \implies C = -\frac {2}{3} \\ \\ \therefore - ln|3-y| = \frac {x-2}{3} \implies ln|3-y| = \frac {2-x}{3} \\ \\ \therefore 3-y = e^{\frac {2-x}{3}} \implies y = 3 - e^{\frac {2-x}{3}}$

Drongoski · Jun 22, 2022

Maths Help (1 Viewer)

Farhanthestudent005

Member

Drongoski

Well-Known Member

Drongoski

Well-Known Member

Users Who Are Viewing This Thread (Users: 0, Guests: 1)