gamja
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- Dec 14, 2022
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- HSC
- 2023
Q5b of the above hsc paper:
- The graphs of y=f(x) [
for x>=0] and y=invf(x) [which I calculated to be
]meet at exactly one point P. Let α be the x-coordinate of P. Explain why α is a root of the equation
x^3 +x -1 = 0.
I let both function formulae equal each other and squared them and eventually came out with a long 5-th degree polynomial. Any ideas? (much appreciated ![Smile :) :)](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
- The graphs of y=f(x) [
![1672655424016.png](/data/attachments/37/37331-bd9357b709e4063c5e72fd94a7993549.jpg)
![1672655519062.png](/data/attachments/37/37332-cd2d6fc18ae8ad46efd9a50d1ae8fd16.jpg)
x^3 +x -1 = 0.