Does anyone know how to do this? (1 Viewer)

[SB257426]

 

[synthesisFR]

uh do u just use discriminant

 

[SB257426]

uh do u just use discriminant

That was legit the first thing i did but didnt get the right answer… unless i suck at algebra

 

[SB257426]

Its C btw

 

[member 6003]

this is basically picking the answer that fits the best, which is why you might be confused.



since then we can say that
satisfies the condition

 

[synthesisFR]

this is basically picking the answer that fits the best, which is why you might be confused.



since then we can say that
satisfies the condition

confused tho on why we let it <0 bc one asymptote is like the denominator has one real solution right so idk

 

[member 6003]

confused tho on why we let it <0 bc one asymptote is like the denominator has one real solution right so idk

discriminant < 0 means no x intercepts so that when you do 1 over, there is no vertical asymptotes but there is still one horizontal asymptote. does that clear the confusion?

 

[synthesisFR]

discriminant < 0 means no x intercepts so that when you do 1 over, there is no vertical asymptotes but there is still one horizontal asymptote. does that clear the confusion?

wait yes but how do u know theres a horizontal im confused lol
are we meant to just quickly visualise a funciton like that using ext 1 skills or what

 

[SB257426]

this is basically picking the answer that fits the best, which is why you might be confused.



since then we can say that
satisfies the condition

i did get the -4a<b<4a inequality but thanks for clearing my doubt

 

[member 6003]

wait yes but how do u know theres a horizontal im confused lol
are we meant to just quickly visualise a funciton like that using ext 1 skills or what

1 over anything has a horizontal asymptote, but yeah you have to visualise the graph

 

[SB257426]

wait yes but how do u know theres a horizontal im confused lol
are we meant to just quickly visualise a funciton like that using ext 1 skills or what

pretty much yeah... think of any curve that is completely above the axis lets say x^2+1. when u graph it .... you will see what i mean

 

[yanujw]

1 over anything has a horizontal asymptote, but yeah you have to visualise the graph

More precisely, has a horizontal asymptote iff at least one of or is non-zero.

 

[Luukas.2]

More precisely, has a horizontal asymptote iff at least one of or is non-zero.

But here, both of those limits are zero, and the horizontal asymptote is - as it must be for for where is a concave up parabola.

 

[yanujw]

But here, both of those limits are zero, and the horizontal asymptote is - as it must be for for where is a concave up parabola.

approaches positive infinity on both sides (since a > 1 > 0), thus both of the limits are non-zero and has a horizontal asymptote.

 

[howcanibesmarter]

lmao my friends were discussing this q last wk

 

[Luukas.2]

approaches positive infinity on both sides (since a > 1 > 0), thus both of the limits are non-zero and has a horizontal asymptote.

I see what has happened, I misread your post as saying that the limit of had to be non-zero. Whoops!