kkk579
hello
Please help, why is it so difficult compared to chemistry? Is it normal to be struggling this early one? Weird how some ppl find physics easier than chemistry, i just dont get how they think that
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Why is physics so hard (1 Viewer)
- Thread starter kkk579
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Aeonium
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which module is this? (or is it just mod 1-2?)
kkk579
hello
Yeah i havent even started mod2 yet and im already struggling with the harder questions on mod1
Aeonium
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suvat, graphs or relative motion?
kkk579
hello
relative motion and suvat but relative motion mainly - for some qs i just sometimes have no clue where to start and the qs really confuse me
Aeonium
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do you have any examples? personally i couldn't find any 'extension' relative motion qns besides "velo of a relative to b is ... –> velo of b relative to ground is ... hence find velo of a"
kkk579
hello
kkk579
hello
These would probably be of a normal
/medium difficulty but since im bad at physics theyre hard
Aeonium
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first step(s): draw a diagram & convert all units to SI units (also is this peak LOL)
do u want me to do it and show working
kkk579
hello
If you could that would be good
is this y11 or 12?
kkk579
hello
11
kkk579
hello
Nah lol its not peak
i will give them a try but I know nothing abt physics
Aeonium
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suvat qns can't really get that hardThese would probably be of a normal
/medium difficulty but since im bad at physics theyre hard
qn 1 (btw this is quite lengthy)
so first step as before:
draw diagram/convert to si units (ngl i just half drew a diagram so i don't think it'd help to see mine). if your tutor hasn't told you already, you can go from km/h –> m/s by dividing 3.6 and vice versa
the displacement between point a and b (ignoring the cars both moving for now) is 10 (distance between front of car and back of truck) + 20 (length of truck) + 10 (distance between final car rear & front of truck) + 4 (length of car) = 44m (i am using the front of the car as a reference point)
now you use the formula
so
so then you can plug that time value back into
kkk579
hello
Answer for that q is t=5s and distance is 144msuvat qns can't really get that hard
qn 1 (btw this is quite lengthy)
so first step as before:
draw diagram/convert to si units (ngl i just half drew a diagram so i don't think it'd help to see mine). if your tutor hasn't told you already, you can go from km/h –> m/s by dividing 3.6 and vice versa
the displacement between point a and b (ignoring the cars both moving for now) is 10 (distance between front of car and back of truck) + 20 (length of truck) + 10 (distance between final car rear & front of truck) + 4 (length of car) = 44m (i am using the front of the car as a reference point)
now you use the formula. you assume that the truck and the car have the same initial velocity (so might asw consider them as relative velo of 0)
so
so then you can plug that time value back into
Aeonium
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yep then mine is correct they just rounded it
kkk579
hello
How to get good at physics
Aeonium
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um tbh idk it's just weird ig just spam qns and know which assumptions to make/which assumptions are used that's the part a lot of people struggle with and if your tutor goes through it then you're fine
Aeonium
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b) what are these terrible units this is def from different syllabus (perhaps university since it looks latex'd)
A. do 45 * 1.852/3.6 * 2 (fuck these units again)
b. tricky tricky B is still moving away when that hapens (i'll also assume the sound wave does not 'inherit' the boat's velocity
c. plug 45 * 1.852/3.6 * time
i think this works but also i was vv distracted when writing this out