yiaghertop
New Member
- Joined
- Jul 26, 2024
- Messages
- 3
- Gender
- Undisclosed
- HSC
- 2026
Have you used this and got the answer? Just saying this because I tried doing tan^2(x) = .... (expanding the tan(x-a)tan(x-b)) and then subbing this tan squared value into tan2x = 2tanx / 1-tan^2(x) . It ends up like a mess up of terms of tanx, tana, tanb which seems unsolvable and it doesnt go anywhere as theres no way to cancel the tanx.expand tan(x-a) and tan(x-b) using the tangent subtracting identity substitute it to the given equation (tan2x=tan(x-a)tan(x-b)) then simplify the numerator and denominator then the equation will become ... and then use the double angle formula for tangent tan2x=2tanx/1-tan2x and substitute into tan2x after some algebraic manipulation.
Thank you so much!
it came from the 3 unit cambridge from the old syllabusim looking rn for more 'fun" q's like this... exercise 2C in both my y11 and y12 3U txtbks dont have further trig or stuff like this.. am i dumb or something where can i find them