Question in math adv test that cost me my grade since idk how to do it (2 Viewers)

[jane1820]

i got 1/3 for it n it was a mark for attempting the question
apparently only one kid got the full thing right from my class and my teachers explanation is too complicated surely theres an easier way

 

[NotBamboo]

hold up let me cook

 

[NotBamboo]

typo???
determine the value of k???
or is it asking if k has not real solutions then what are the other values?

 

[jane1820]

typo???
determine the value of k???

Lmao yh

 

[jane1820]

@NotBamboo ill try to solve it again too

 

[Shavi Masee]

what was the answer?
the x and y makes it uglyy ughh

 

[NotBamboo]

Lmao yh

no i think the punctuation is wrong
i think they want k to have no real solutions

wait no its of
no wonder they never became english teachers

 

[NotBamboo]

what was the answer?

currently trying to decode the last sentence of the question

its a 3 variable simultaneous equation
but with only 2 lines
so the trick is that information is given about k in the last line
but im trying to figure out what on earth this means

 

[jane1820]

Nope i couldnt solve it

 

[jane1820]

no i think the punctuation is wrong
i think they want k to have no real solutions

No k has solutions

so towards the end apparently it should be
(system of equations that contains k) = no real solution

 

[jane1820]

what was the answer?
the x makes it uglyy ughh

I dont want to post the answers just yet (obviously the teacher gave answers but as i said its too complicated surely theres an easier way)

 

[jane1820]

Where are the math goats to solve this?
anyone doing ext 2 or ext 1 math and needs a break w a yr 11 math adv algebra question?

 

[jane1820]

Im avoiding looking at the answer (i actually forgot the steps but ik solutions of k) and i retried so many times

 

[Shavi Masee]

No k has solutions

so towards the end apparently it should be
(system of equations that contains k) = no real solution

i'm so confused how can k have to real solution but have a solution (i don't think i've done this in school T-T)

 

[NotBamboo]

Nope i couldnt solve it

gotta go dinner
ill do it after and get back to u

 

[jane1820]

alr chat ill give a hint

towards the end u should get a fraction with a quadratic equation at the bottom

any fraction on zero is undefined hence no real solution

but as i said i dont remember the steps i just remember what k equals

 

[cheesynooby]

theres a hint in the question: they tell u that they're linear equations.
usually 2 linear equations (aka lines) intersect once - 1 solution
but to get 0 real solutions they must thus not intersect at all i.e. they are parallel lines with different y intercepts
so just rearrange the equations into gradient intercept form and equate the gradients

 

[jane1820]

theres a hint in the question: they tell u that they're linear equations.
usually 2 linear equations (aka lines) intersect once - 1 solution
but to get 0 real solutions they must thus not intersect at all i.e. they are parallel lines with different y intercepts
so just rearrange the equations into gradient intercept form and equate the gradients

I tried doing that in my exam but it didnt work for me (i think thats why i got 1 mark bc i knew one step out of three)

ill try it again this way

 

[Shavi Masee]

theres a hint in the question: they tell u that they're linear equations.
usually 2 linear equations (aka lines) intersect once - 1 solution
but to get 0 real solutions they must thus not intersect at all i.e. they are parallel lines with different y intercepts
so just rearrange the equations into gradient intercept form and equate the gradients

woahhh ur smart af :0

yet i still can't do it

 

[jane1820]

@cheesynooby i got k=2/-2 but thats only k=-2 is ONE of the solutions + i didnt get a quadratic equation so i did it wrong