F
Reaction score
107

## Profile posts Latest activity Postings About

• Bro change as soon as you can, trust me you will regret not choosing. I suggest that you speak with your English Head teacher tomorrow asap and move in the ADVENG class as soon you can.

NB: We can help each other with identical subs we have!
I've been doing lots of work on Circle Geo so I'm getting my head around it...
Yeah I did, but I was in Advanced for a while now, so I forgot to change it. Thanks
ATAR aim would be around 90-5+...
Thinking of dropping 3U if it doesn't go well :l Its very hard.
you are my favourite person right now
thank you so much for the past nsg maths test papers
im going into year 10 so it will be of great use to me
ily person ^-^
who is that? and probably not
I was actually thinking of the same thing this morning when I woke up.
Yepp your on the ball, medicine, becoming a doctor one day is my ultimate dream bro!
a beautiful kebab box
So bro what have you been doing these days? When are your yearly exams?
lol, why do u think that ?
Honestly... i didn't find the work that great, it was tedious and repetitive. But due to doing standard i kept the same teacher for 3 years consecutively. This teacher knew about my general lack of motivation and the fact that i used to be socially awkward as fuck and worked around it, making me kind of enjoy coming to English, i also had good classmates who i joked around with. By the time i started doing daily essays and putting effort in i found that i just enjoyed coming to class... it was a good opportunity to have a discussion and joke around. 'Twas just a good experience i guess

I honestly think that in my current state i could of handled 3U English, but i would likely still be an unmotivated UWSCollege candidate if it wasn't for my time in Standard
e = 1/0! + 1/1! + 1/2! + ...

let e = p/q, S(n) = 1/0! + 1/1! + ... + 1/n!

e - S(n) = 1/(n+1)! + 1/(n+2)! + .... < 1/(n+1)! (1 + 1/(n+1) + 1/(n+1)^2 + ...) = 1/((n)(n!))

e - S(n) > 0

0< n n! e - n n! S(n) < 1

Therefore n n! e - n n! S(n) is not an integer

Since e = p/q, and take n > q, then n! e is an integer

So n n! e - n n! S(n) is an integer

So n n! e - n n! S(n) is an integer and is not an integer