Recent content by kawaiipotato

1. Integration MC Question - North Sydney Boys 2017 Trial

You can also reason it like this: If f takes non-negative values on [-a,0], then the first term is non-negative. The second term will be non-negative because of the absolute value. Then the sum of those two is non-negative, meaning that if we had a function f with the previously mentioned...

Just a note that you should expect 1/2 because the number of desired outcomes are equal in both cases.
3. Probability

Count the ways to fix the boys in a circle first. Then count the ways to place the girls between the boys. This will be your desired outcomes, and your total outcomes is just 7!.
4. Is it ok to use other peoples code with reference in a school assessment ?

Probably depends on your school's policies as well as your specific class.
5. UNSW 17/S2 Official Results Thread

Just got mine, zID starts with z511
6. UNSW 17/S2 Official Results Thread

All MATH provisional marks have been posted on the Math&Stats Portal page.

8. Just realized my school disposes of lead containing solutions down the sink?

For some chemicals, I remember that our teacher would have a large bucket where we poured everything into it at the end of the practical lesson.
9. VCE Maths questions help

Yes it is, my bad. You would use this matrix in the same method as how I did it the first time around.
10. VCE Maths questions help

$\noindent The inverse matrix of the transformation is$-\frac{1}{6}\begin{pmatrix}-3 && 0\\0 &&2\end{pmatrix}$. \\ Can you go from here?$

14. Inverse Cosine Function

Oh yes, I meant there is a similar case for sinx = 0. (Try and see the cases using the Unit Circle, it helps a lot).
15. Inverse Cosine Function

$\noindent This is a special case. Do you know the Unit Circle? \\ For the ''how?'': it's basically because$\cos$has roots at$x= 0, \pi/2,-\pi,2$. From what you know,$\cos$has periodicity$2\pi$. Then since$x=\pi/2,-\pi/2$are roots, then$x=\pi/2 - 2\pi,-\pi/2 + 2\pi\$ are roots as well...